x^2+3-x=x^2+10x-7

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Solution for x^2+3-x=x^2+10x-7 equation: 



x^2+3-x=x^2+10x-7

We move all terms to the left:

x^2+3-x-(x^2+10x-7)=0

We add all the numbers together, and all the variables

x^2-1x-(x^2+10x-7)+3=0

We get rid of parentheses

x^2-x^2-1x-10x+7+3=0

We add all the numbers together, and all the variables

-11x+10=0

We move all terms containing x to the left, all other terms to the right

-11x=-10

x=-10/-11

x=10/11

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